Algebra Questions and Answers with Solution PDF

By Last updated Jun 15, 2020

Algebra Questions and Answers PDF

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RRB JE, SSC CGL, SSC CHSL, RRB NTPC Exams are started after a few months. In those exams, almost Questions are coming from Algebra Questions and Answers PDF Maths .so Maths Paper is important in all exams. Common questions and answers are placed in algebra questions pdf, which has been put together in most examinations, you can download this PDF Notes very simply by clicking on the Download Button at the bottom.

This post is dedicated to downloading our PDFEXAM for free PDFs, which are the latest exam pattern based algebra questions pdf for RRB JE, SSC CGL, SSC CHSL, RRB NTPC, etc.

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Importance of Maths:

Every exam you will get almost questions from Math paper. So candidates must focus on Maths and download these algebra questions PDF to get important questions with the best solutions. We have put all Previous Year Questions of Maths that are Asked in various Govt & Private Exam.

Algebra

Algebra is the study of mathematical symbols and the rules for manipulating these symbols.

Important formula:-

Here is a list of Algebraic formulas –

a2 – b2 = (a – b)(a + b)
(a+b)2 = a2 + 2ab + b2
a2 + b2 = (a – b)2 + 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a – b)3 = a3 – 3a2b + 3ab2 – b3
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4)
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4)
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)

Roots of Quadratic Equation

For a quadratic equation ax2 + bx + c where a ≠ 0, the roots will be given by the equation as −b±b2−4ac√2a
Δ = b2 − 4ac is called the discrimination.
For real and distinct roots, Δ > 0
For real and coincident roots, Δ = 0
For non-real roots, Δ < 0
If α and β are the two roots of the equation ax2 + bx + c then, α + β = (-b / a) and α × β = (c / a).
If the roots of a quadratic equation are α and β, the equation will be (x − α)(x − β) = 0

501 Algebra Important Questions and Answers PDF

Some Questions from Algebra-

Q1. If $x^{3} + y^{3} = 9$ and $x + y = 3$ then the value of $x^{4} + y^{4}$ is,

Answer: 4

Q2 For any real number $x$ the maximum value of $4 - 6 x - x^{2}$ is,

Answer: 4

Q3 If $5^{\sqrt{x}} + 12^{\sqrt{x}} = 13^{\sqrt{x}}$ then value of $x$ is,

$\frac{25}{4}$
4
6
9

Answer: 2

Q4 If $x^{2} + 2 = 2 x$ then the value of $x^{4} - x^{3} + x^{2} + 2$ will be,

0
1
-1
$\sqrt{2}$

Answer: 1

Algebra Questions with Complete Solutions PDF

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Maths Notes PDF

Maths Questions

Q.1. 300 मीटर की दूरी से क्षैffतिज तल पर स्थित किसी शीर्ष की चोटी का उन्नयन कोण 30 अंश है। शिखर की ऊंचाई ज्ञात करो –

[A] 145.20मीटर

[B] 173.20 मीटर

[C] 145मीटर

[D] 200मीटर

Answer: [B]

Q.2. 505 मीटर लंबा एक खम्भा दीवार के सहारे जमीन के 60 अंश के कोण पर टिका हुआ हो, तो खंभा दीवार की किस ऊंचाई पर पहुंचेगा –

[A] 20.36मीटर

[B] 12.99 मीटर

[C] 14मीटर

[D] 18 मीटर

Answer: [B]

Q.3. कितने वर्षो में 12 प्रतिशत वार्षिक दर से 3000 रूपए का साधारण ब्याज 1080 रूपए हो जाएगा-

[A] 9वर्ष

[B] 4वर्ष

[C] 3 वर्ष

[D] 7 वर्ष

Answer: [C]

Q.4. किसी त्रिभुज की भुजाएं 3:4:6 के अनुपात में है, त्रिभुज है –

[A] समकोण

[B] न्यूनकोण

[C] अधिक कोण

[D] इनमें से कोई नहीं

Answer: [C]

Q.5. किसी त्रिभुज की भुजाएं 3:4:5 के अनुपात में है। त्रिभुज के सबसे बड़े कोण का माप होगा –

[A] 63 अंश

[B] 68 अंश

[C] 71अंश

[D] 75 अंश

Answer: [D]

Q.6 एक शंकु, एक गोलाई, और एक बेलन एकसमान आधार वाले हैं, और उनकी ऊंचाई भी एक समान है। तद्नुसार उ न तीनों के आयतन का अनुपात क्या होगा –

[A] 3:3:1

[B] 3:7:1

[C] 1:2:3

[D] इनमें से कोई नहीं

Answer: [C]

Q.7. यदि किसी वस्तु के क्रय मूल्य तथा विक्रय मूल्य 10:11 के अनुपात में हो तो लाभ प्रतिशत ज्ञात कीजिए-
[A] 10
[B] 6
[C] 5
[D] 1

Answer: [A]

Q.8. प्रथम 100 धन पूर्णाकों का औसत होगा –

[A] 49.5

[B] 47

[C] 52

[D] 50.5

Answer: [D]

Q.9. यदि किसी वस्तु को 200 प्रतिशत के लाभ से बेचा जाता है, तो इसके क्रय मूल्य का इसके विक्रय मूल्य से अनुपात होगा –

[A] 1:7

[B] 2:1

[C] 1:3

[D] 6:1

Answer: [C]

Q.10. 450 रूपए में कुछ टेनिस बाल खरीदे गए। यदि प्रत्येक बाल 15 रूपए सस्ता होता तो उतनी ही राशि में 5 बाल और खरीदे जा सकते थे। खरीदे गए बाल की संख्या ज्ञात कीजिये –
[A] 6
[B] 7

[C] 10

[D] 74

Answer: [C]

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