Maths Tricks Arithmetic Notes 2023 PDF Download

Math Trick Notes in Hindi

By Admin On Feb 2, 2023

Maths Tricks Arithmetic Notes 2023 PDF Download

Math Trick Notes in Hindi are most important for all Sarkari exams. so today we Provide you with Arithmetic Maths Questions Answers PDF in Hindi for SSC CGL Exam for competitive exams with important tricks. This Mathematics Questions and Answers PDF for SSC with Solutions PDF for SSC, UPSC, Railway, and All Competitive Exams. We Know That all Sarkari Exams are started after a few months. In those exams, / Many Questions are coming from, Maths. so Downloading the Best Math Trick in Hind Book PDF for competitive exams for SSC, UPSC, Railway and All Competitive Exams is important in all GOVT. Exams. Common questions are placed in the Maths for Competitive Exams PDF in Hindi for SSC, UPSC, Railway, and All Competitive Exams, which has been put together in most examinations, you can download, which has been put together in most examinations, you can download this maths shortcut tricks pdf free download very simply by clicking on the Download Button at the bottom.

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Maths Notes PDF

Maths Questions and Answers for Competitive Exams

1. A student has to score 30% marks to get through. If he gets 30 marks and fails by 30 marks. Find the maximum marks set for the examination.
(a) 180 (b) 210 (c) 200 (d) 220 (Ans : c)

2. A candidate scores 25% and fails by 60 marks, while another candidate who scores 50% marks, get 40 marks more than the mini- mum required marks to pass the examination. Find the maximum marks for the examination–
(a) 360 (b) 380 (c) 400 (d) 420 (Ans : c)

3. The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be–
(a) 12 years (b) 14 years (c) 18 years (d) 20 years (Ans : d)

4. An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is–
(a) 2% (b) 2. 02% (c) 4% (d) 4. 04% (Ans : d)

5. A clock is started at noon. By 10 minutes past 5, the hour hand has turnod through–
(a) 1450 (b) 1500 (c) 1550 (d) 1600 (Ans : c)

6. An automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes–
(a) 10% (b) 10.25% (c) 10.5% (d) 10.75% (Ans : c)

7. (√10 – 3) (√10 + 3) = ?
(a) 1 (b) 2 (c) 2√10 (d) 6 (Ans : a)

8. Rajesh walked 25 m towards south. Then he turned to his left and walked 20 m. He then turned to his left and walked 25 m. He again turned to his right and walked-15 m. At what distance is he from the starting point and in which direction?
(a) 35 m East (b) 35 m North (c) 30 m West (d) 45 m East (Ans : a)

9. A lent Rs. 600 to B for 2 years and Rs. 150 to C for 4 years and received Rs. 90 from both as interest. Find out rate of interest, simple interest being calculated.
(a) 5% (b) 7% (c) 8% (d) 9% (Ans : a)

10. In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
(a) 70% (b) 80% (c) 90% (d) None of the above (Ans : d)

11. A sum of Rs. 468. 75 was lent out at simple interest and at the end of 1 year 8 months the total amount was Rs. 500. Find the rate of interest per annum.
(a) 4% (b) 5% (c) 6% (d) 7% (Ans : a)

12. Rs. 800 amounts to Rs. 920 in 3 years at simple interest. If the interest rate is increased by 3% to how much would it amount?
(a) Rs. 892 (b) Rs. 829 (c) Rs. 992 (d) Rs. 929 (Ans : c)

13. Amit said, “This girl is the wife of the grandson of my mother”. How is Amit related to the girl?
(a) Brother (b) Grandfather (c) Husband (d) Father-in-Law (Ans : d)

14. Pointing towards a man, a woman said, “His mother is the only daughter of my mother. ” How is the woman related to the man ?
(a) Mother (b) Grandmother (c) Sister (d) Daughter (Ans : a)

15. In a coding system, PEN is written by as NZO and BARK as CTSL. How can we write PRANK?
(a) CSTZN (b) NSTOL (c) NTSLO (d) NZTOL (Ans : b)

16. If TEACHER is coded a LMKJNMP, then how will HEART be coded ?
(a) NMAPL (b) NMPKL (c) NPKML (d) NMKPL (Ans : d)

17. Find the relationship as expressed in the given pair–
Calendar : Dates : : Dictioruuy 😕
(a) Vocabulary (b) Language (c) Words (d) Book (Ans : a)

18. Find the relationship as expressed in the given pair–
Circle : Circumference : : Square : ?
(a) Volume (b) Area (c) Diagonal (d) Perimeter (Ans : d)

19. Find the relationship as expressed in the given pair–
Breeze : Cyclone : : Drizzle : ?
(a) Earthquake (b) Storm (c) Flood (d) Downpour (Ans : d)

20. Find the relationship as expressed in the given pair–
Import : Export : : Expenditure : ?
(a) Deficit (b) Revenue (c) Debt (d) Tax (Ans : b)

21. Find the missing number–
24, 60, 120, 210, ?
(a) 300 (b) 336 (c) 420 (d) 525 (Ans : b)

22. Find the missing number–
3, 12, 27, 48, 75, 108, ?
(a) 147 (b) 162 (c) 183 (d) 192 (Ans : a)

23. Arrange the following words according to Dictionary arrangement–
1. Epitaxy 2. Episode 3. Epigene 4. Epitome
(a) 1, 2, 3, 4 (b) 3, 2, 4, 1 (c) 3, 2, 1, 4 (d) 4, 2, 1, 3 (Ans : c)

24. Fresh grapes contain 80% water while dry grapes contain 10% water. If the weight of dry grapes is 250 kg, what is the total weight when it was fresh?
(a) 1000 kg (b) 1100 kg (c) 1125 kg (d) 1225 kg (Ans : c)

25. A seller allows a discount of 5% on a watch. If he allows a discount of 7% he earns Rs. 15 less in the profit. What is the marked price?
(a) Rs. 697.5 (b) Rs. 712.5 (c) Rs. 750 (d) Rs. 817.5 (Ans : c)

26. An Aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 2/3 hours, it must travel at a speed of–
(a) 300 kmph (b) 360 kmph (c) 600 kmph (d) 720 kmph (Ans : d)

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Maths Question Answer

Q 1 . एक रेलगाड़ी किसी स्टेशन पर खड़े एक व्यक्ति की 20 सेकेण्ड में पार कर जाती। यदि रेलगाड़ी की चाल 20मी./से. हो तो रेलगाड़ी की लम्बाई ज्ञात करो?
(A). 200मी.

(B). 400मी.

(C). 600मी.

(D). 120मी.

Ans. 400मी.

Q 2 . 7 व्यक्तियों का औसत आयु 22 वर्ष है यदि 1 व्यक्ति उनके साथ मिल जाता है तो उनकी औसत आयु 1 वर्ष बढ़ जाता है तो जो व्यक्ति आया उसकी आयु कितना है?
(A). 26 वर्ष

(B). 28 वर्ष

(C). 30 वर्ष

(D). 32 वर्ष

Ans. 30 वर्ष

Q 3 . 5 मित्रों की औसत आयु 40 वर्ष है उनमें से एक मित्र चला जाता है तो अब औसत आयु 38 वर्ष हो जाता है। हटा गया मित्र की आयु कितना है ?
(A). 44 वर्ष

(B). 48 वर्ष

(C). 40 वर्ष

(D). 36 वर्ष

Ans. 48 वर्ष

Q 4 . यदि कोई ट्रेन 5 मिनट में 11 किमी. चलता है तो उस ट्रेन की चाल किमी./घंटा में कितना होगा?
(A). 121 किमी./घंटा

(B). 132 किमी./घंटा

(C). 123 किमी./घंटा

(D). 125 किमी./घंटा

Ans. 132 किमी./घंटा

Q 5 . एक ट्रेन एक प्लेटफार्म जिसकी लम्बाई 120 मीटर है उसे 10 सेकेण्ड में पार कर जाती है और प्लेटफार्म पर खड़े एक व्यक्ति को 65 सेकेण्ड में पार कर जाती है तो ट्रेन की चाल किमी./घंटा में बताओ?
(A). 90 किमी./घंटा

(B). 105 किमी./घंटा

(C). 108 किमी./घंटा

(D). 111 किमी./घंटा

Ans. 108 किमी./घंटा

Q 6 . स्थान A से B की दूरी को एक कार 50 किमी./घंटा की गति से जाता है और 30 किमी./घंटा की गति से आता है तो कार का औसत चाल ज्ञात कीजिए ?
(A). 35 किमी./घंटा

(B). 37.5 किमी./घंटा

(C). 42.5 किमी./घंटा

(D). 45 किमी./घंटा

Ans. 37.5 किमी./घंटा

Q 7 . क्रमागत 7 सम संख्याओं का औसत मान 24 है तो सबसे छोटी संख्या ज्ञात कीजिए ?
(A). 18

(B). 22

(C). 16

(D). 20

Ans. 18

Q 8 . क्रमागत 7 सम संख्याओं का औसत मान 24 है तो सबसे छोटी संख्या ज्ञात कीजिए ?
(A). 18

(B). 22

(C). 16

(D). 20

Ans. 18

Q 9 . एक समूह में 10 लड़को का औसत भार 21 किलो. है अगर प्रथम 5 लड़को का औसत भार 20 किलो हो और अगले 4 लड़को का औस भार 22 किलो हो तो अन्तिम लड़के का वजन कीजिए।
(A). 20 किलो.

(B). 21 किलो.

(C). 22 किलो.

(D). 23 किलो.

Ans. 22 किलो.

Q 10 . 17 छात्रों का औसत भार 17 किलो. है गलती से 19 और 21 के स्थान पर 11 तथा 12 जोड़ दिया जाता है तो उनका सही औसत भार क्या होगा ?
(A). 15 किलो.

(B). 16.5 किलो.

(C). 17 किलो.

(D). 17.5 किलो.

Ans. 17 किलो.

Maths Questions Answers

1. Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.

Solution:

Let the 1st paycheck be x (integer).

Mrs. Rodger got a weekly raise of $ 145.

So after completing the 1st week she will get $ (x+145).

Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

2. The value of x + x(x^x) when x = 2 is:

(a) 10, (b) 16, (c) 18, (d) 36, (e) 64

Solution:

x + x(x^x)

Put the value of x = 2 in the above expression we get,

2 + 2(2²)

= 2 + 2(2 × 2)

= 2 + 2(4)

= 2 + 8

= 10

Answer: (a)

3. Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents

Solution:

Selling price of the first pipe = $1.20

Profit = 20%

Let’s try to find the cost price of the first pipe

CP = Selling price – Profit

CP = 1.20 – 20% of CP

CP = 1.20 – 0.20CP

CP + 0.20CP = 1.20

1.20CP = 1.20

CP = $\frac{1.20}{1.20}$

CP = $ 1

Selling price of the Second pipe = $1.20

Loss = 20%

Let’s try to find the cost price of the second pipe

CP = Selling price + Loss

CP = 1.20 + 20% of CP

CP = 1.20 + 0.20CP

CP – 0.20CP = 1.20

0.80CP = 1.20

CP = $\frac{1.20}{0.80}$

CP = $1.50

Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50

And total selling price of the two pipes = $1.20 + $1.20 = $2.40

Loss = $2.50 – $2.40 = $0.10

Therefore, Mr. Jones loss 10 cents.

Answer: (d)

4. The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:

(a) 587 × 10⁸ miles, (b) 587 × 10¹⁰ miles, (c) 587 × 10^-10 miles, (d) 587 × 10¹² miles, (e) 587 × 10^-12 miles

Solution:

The distance of the light travels in 100 years is:

5,870,000,000,000 × 100 miles.

= 587,000,000,000,000 miles.

= 587 × 10¹² miles.

Answer: (d)

5. A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at:

(a) 6 % , (b) 6.1 %, (c) 6.2 %, (d) 6.3 %, (e) 6.4 %

Solution:

Income from $ 4000 at 5 % in one year = $ 4000 of 5 %.

= $ 4000 × 5/100.

= $ 4000 × 0.05.

= $ 200.

Income from $ 3500 at 4 % in one year = $ 3500 of 4 %.

= $ 3500 × 4/100.

= $ 3500 × 0.04.

= $ 140.

Total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340.

Remaining income amount in order to have a yearly income of $ 500 = $ 500 – $ 340.

= $ 160.

Total invested amount = $ 4000 + $ 3500 = $7500.

Remaining invest amount = $ 10000 – $ 7500 = $ 2500.

We know that, Interest = Principal × Rate × Time

Interest = $ 160,

Principal = $ 2500,

Rate = r [we need to find the value of r],

Time = 1 year.

160 = 2500 × r × 1.

160 = 2500r

160/2500 = 2500r/2500 [divide both sides by 2500]

0.064 = r

r = 0.064

Change it to a percent by moving the decimal to the right two places r = 6.4 %

Therefore, he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year.

Answer: (e)

6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

Solution:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

Answer: (b)

7. If (0.2)^x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:

(a) -10.0, (b) -0.5, (c) -0.4, (d) -0.2, (e) 10.0

Solution:

(0.2)^x = 2.

Taking log on both sides

log (0.2)^x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (²/₁₀) = 0.3010.

x [log 2 – log 10] = 0.3010.

x [log 2 – 1] = 0.3010,[since log 10=1].

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = ^0.3010/_-0.699.

x = -0.4306….

x = -0.4 (nearest tenth)

Answer: (c)

8. If 10^2y = 25, then 10^-y equals:

(a) ^-1/₅, (b) ¹/₆₂₅, (c) ¹/₅₀, (d) ¹/₂₅, (e) ¹/₅

Solution:

10^2y = 25

(10^y)² = 5²

10^y = 5

¹/_10^y = ¹/₅

10^-y = ¹/₅

Answer: (e)

9. The fraction ^(5x-11)/_{(2x² + x – 6)} was obtained by adding the two fractions ^A/_{(x + 2)} and ^B/_{(2x – 3)}. The values of A and B must be, respectively:

(a) 5x, -11, (b) -11, 5x, (c) -1, 3, (d) 3, -1, (e) 5, -11

Solution:

Answer: (d)

10. The sum of three numbers is 98. The ratio of the first to the second is ²/₃, and the ratio of the second to the third is ⁵/₈. The second number is:

(a) 15, (b) 20, (c) 30, (d) 32, (e) 33

Solution:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is ²/₃.

x/y = ²/₃.

x = ²/₃ × y.

x = ^2y/₃.

The ratio of the second to the third is ⁵/₈.

^y/_z = ⁵/₈.

^z/_y = ⁸/₅.

z = ⁸/₅ × y.

z = ^8y/₅.

Put the value of x = ^2y/₃ and z = ^8y/₅ in (i).

^2y/₃ + y + ^8y/₅ = 98

^49y/₁₅ = 98.

49y = 98 × 15.

49y = 1470.

y = ¹⁴⁷⁰/₄₉.

y = 30 .

Therefore, the second number is 30.

Answer: (c)

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