Quantum CAT by Sarvesh Kumar Verma PDF Free Download
Quantum CAT by Sarvesh Kumar Verma PDF Free Download
Upcoming GOVT. Vacancies FROM Railway. THESE Exams are started after a few months. In those exams, / Many Questions are coming from, MATHS. so Quantum Cat PDF is important in all GOVT. Exams. Common questions are placed in Quantum Cat PDF, which has been put together in most examinations, you can download these PDF Notes very simply by clicking on the Download Button at the bottom.
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Quantum Cat PDF , Quantum Cat PDF , Quantum Cat PDF . Paramount Maths, Rakesh Yadav Maths Notes PDF, Maths Shortcut Tricks. In “ Quantum Cat PDF ” is providing you the GK, REASONING, and MATHES TOPICS with ANSWER. Where you can easily get the logic of the questions. Quantum Cat PDF, Quantum Cat PDF Plays an important role in EXAMS. Quantum Cat PDFs are Provided free to download.
Importance of Quantum Cat PDF :
For every exam you will get at least many questions from Quantum Cat PDF. So candidates must focus on Quantum Cat PDF and download this Quantum Cat PDF to get important questions with the best ANSWERS. We have put all Previous Year Questions of Quantum Cat PDF that are Asked in various GOVT. Exams.
Quantum Cat PDF covered thoroughly under the guidance of subject experts. This Quantum Cat PDF mainly targeting Quantum Cat PDF.
Quantum Cat PDF के नोट्स की डायरेक्ट लिंक हमने यहां उपलब्ध करा दी है! जिसे आप निचे दिए गए डाउनलोड लिंक पर क्लिक करके डाउनलोड कर सकते है! अगर आपको किसी भी तरीके की परेशानी हो तो आप हमे निचे दिए गए कमेंट बॉक्स में टाइप कर सकते है! हम जल्द से जल्द आपकी सहायता करेंगे! हमे आपकी सहायता करने में ख़ुशी होगी!
Topics Are Covered in Quantum Cat PDF
- Fundamentals
- Averages
- Allegations
- Ratio
- Proportion & Variation
- Percentages, Profit
- Loss & Discount
- CI/SI/Installments
- Time & Work
- Time
- Speed & Distance
- Mensuration
- Trigonometry
- Geometry
- Elements of Algebra
- Theory of Equations
- Set Theory
- Logarithm
- Functions & Graph
- Sequence
- Series & Progressions
- Permutations & Combinations
- Probability and Co-ordinate Geometry
About Quantum Cat PDF: TOPICS OF MATHS
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Computer Topicwise Short Tricks > Click Here To Download | EnvironmentTopicwise Free PDF > Click Here To Download |
UPSC Notes > Click Here To Download | SSC Notes Download > Click Here To Download |
Quantum CAT Question Answers:-
1. Which is greater than 4?
(a) 5,
(b) -5,
(c) -1/2,
(d) -25.
Solution:
5 greater than 4.
Answer: (a)
2. Which is the smallest?
(a) -1,
(b) -1/2,
(c) 0,
(d) 3.
Solution:
The smallest number is -1.
Answer: (a)
3. Combine terms: 12a + 26b -4b – 16a.
(a) 4a + 22b,
(b) -28a + 30b,
(c) -4a + 22b,
(d) 28a + 30b.
Solution:
12a + 26b -4b – 16a.
= 12a – 16a + 26b – 4b.
= -4a + 22b.
Answer: (c)
4. Simplify: (4 – 5) – (13 – 18 + 2).
(a) -1,
(b) –2,
(c) 1,
(d) 2.
Solution:
(4 – 5) – (13 – 18 + 2).
= -1-(13+2-18).
= -1-(15-18).
= -1-(-3).
= -1+3.
= 2.
Answer: (d)
5. What is |-26|?
(a) -26,
(b) 26,
(c) 0,
(d) 1
Solution:
|-26|
= 26.
Answer: (b)
6. Multiply: (x – 4)(x + 5)
(a) x2 + 5x – 20,
(b) x2 – 4x – 20,
(c) x2 – x – 20,
(d) x2 + x – 20.
Solution:
(x – 4)(x + 5).
= x(x + 5) -4(x + 5).
= x2 + 5x – 4x – 20.
= x2 + x – 20.
Answer: (d)
7. Factor: 5x2 – 15x – 20.
(a) 5(x-4)(x+1),
(b) -2(x-4)(x+5),
(c) -5(x+4)(x-1),
(d) 5(x+4)(x+1).
Solution:
5x2 – 15x – 20.
= 5(x2 – 3x – 4).
= 5(x2 – 4x + x – 4).
= 5{x(x – 4) +1(x – 4)}.
= 5(x-4)(x+1).
Answer: (a).
8. Factor: 3y(x – 3) -2(x – 3).
(a) (x – 3)(x – 3),
(b) (x – 3)2,
(c) (x – 3)(3y – 2),
(d) 3y(x – 3).
Solution:
3y(x – 3) -2(x – 3).
= (x – 3)(3y – 2).
Answer: (c).
9. Solve for x: 2x – y = (3/4)x + 6.
(a) (y + 6)/5,
(b) 4(y + 6)/5,
(c) (y + 6),
(d) 4(y – 6)/5.
Solution:
2x – y = (3/4)x + 6.
or, 2x – (3/4)x = y + 6.
or, (8x -3x)/4 = y + 6.
or, 5x/4 = y + 6.
or, 5x = 4(y + 6).
or, 5x = 4y + 24.
or, x = (4y + 24)/5.
Therefore, x = 4(y + 6)/5.
Answer: (b).
10. Simplify:(4x2 – 2x) – (-5x2 – 8x).
Solution:
(4x2 – 2x) – (-5x2 – 8x)
= 4x2 – 2x + 5x2 + 8x.
= 4x2 + 5x2 – 2x + 8x.
= 9x2 + 6x.
= 3x(3x + 2).
Answer: 3x(3x + 2)
11. Find the value of 3 + 2 • (8 – 3)
(a) 25,
(b) 13,
(c) 17,
(d) 24,
(e) 15.
Solution:
3 + 2 • (8 – 3)
= 3 + 2 (5)
= 3 + 2 × 5
= 3 + 10
= 13
Answer: (d)
12. Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?
Solution:
33/4 ÷ 4 pounds.
= (4 × 3 + 3)/4 ÷ 4 pounds.
= 15/4 ÷ 4 pounds.
= 15/4 × 1/4 pounds.
= 15/16 pounds.
Now we know that, 1 pound = 16 ounces.
Therefore, 15/16 pounds = 15/16 × 16 ounces.
= 15 ounces.
Answer: 15 ounces.
13. Factor: 16w3 – u4w3
Solution:
16w3 – u4w3.
= w3(16 – u4).
= w3(42 – ((u2)2).
= w3(4 + u2)(4 – u2).
= w3(4 + u2)(22 – u2).
= w3(4 + u2)(2 + u)(2 – u).
Answer: w3(4 + u2)(2 + u)(2 – u).
14. Factor: 3x4y3 – 48y3.
Solution:
3x4y3– 48y3.
= 3y3(x4 – 16).
= 3y3[(x2)2 – 42].
= 3y3(x2 + 4)(x2 – 4).
= 3y3(x2 + 4)(x2 – 22).
= 3y3(x2 + 4)(x + 2)(x -2).
Answer: 3y3(x2 + 4)(x + 2)(x -2)
15. What is the radius of a circle that has a circumference of 3.14 meters?
Solution:
Circumference of a circle = 2πr.
Given, the circumference = 3.14 meters.
Therefore,
2πr = Circumference of a circle
or, 2πr = 3.14.
or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].
or, 6.28r = 3.14.
or, r = 3.14/6.28.
or, r = 0.5.
Answer: 0.5 meter.
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