Quantum CAT by Sarvesh Kumar Verma PDF Free Download

Quantum CAT by Sarvesh Kumar Verma PDF Free Download

 Upcoming GOVT.  Vacancies FROM  Railway. THESE Exams are started after a few months. In those exams, / Many Questions are coming from, MATHS. so Quantum Cat PDF  is important in all GOVT. Exams. Common questions are placed in Quantum Cat PDF, which has been put together in most examinations, you can download these PDF Notes very simply by clicking on the Download Button at the bottom.

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Quantum Cat PDF , Quantum Cat PDF  , Quantum Cat PDF  . Paramount Maths, Rakesh Yadav Maths Notes PDF, Maths Shortcut Tricks. In  “ Quantum Cat PDF  ” is providing you the GK, REASONING, and MATHES TOPICS   with ANSWER. Where you can easily get the logic of the questions. Quantum Cat PDF, Quantum Cat PDF  Plays an important role in EXAMS. Quantum Cat PDFs are Provided free to download.

Importance of Quantum Cat PDF  :

For every exam you will get at least many questions from Quantum Cat PDF. So candidates must focus on Quantum Cat PDF  and download this Quantum Cat PDF   to get important questions with the best ANSWERS. We have put all Previous Year Questions of Quantum Cat PDF   that are Asked in various GOVT. Exams.

Quantum Cat PDF covered thoroughly under the guidance of subject experts. This Quantum Cat PDF mainly targeting Quantum Cat PDF.

Quantum Cat PDF  के नोट्स की डायरेक्ट लिंक हमने यहां उपलब्ध करा दी है! जिसे आप निचे दिए गए डाउनलोड लिंक पर क्लिक करके डाउनलोड कर सकते है! अगर आपको किसी भी तरीके की परेशानी हो तो आप हमे निचे दिए गए कमेंट बॉक्स में टाइप कर सकते है! हम जल्द से जल्द आपकी सहायता करेंगे! हमे आपकी सहायता करने में ख़ुशी होगी!

Topics Are Covered in Quantum Cat PDF

  1. Fundamentals
  2. Averages
  3. Allegations
  4. Ratio
  5. Proportion & Variation
  6. Percentages, Profit
  7. Loss & Discount
  8. CI/SI/Installments
  9. Time & Work
  10. Time
  11. Speed & Distance
  12. Mensuration
  13. Trigonometry
  14. Geometry
  15. Elements of Algebra
  16. Theory of Equations
  17. Set Theory
  18. Logarithm
  19. Functions & Graph
  20. Sequence
  21. Series & Progressions
  22. Permutations & Combinations
  23. Probability and Co-ordinate Geometry

About Quantum Cat PDF: TOPICS OF MATHS

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UPSC Notes > Click Here To Download SSC Notes Download > Click Here To Download

 

Quantum CAT Question Answers:-

1. Which is greater than 4?

(a) 5,

(b) -5,

(c) -1/2,

(d) -25.

Solution:

5 greater than 4.

Answer: (a)

2. Which is the smallest?

(a) -1,

(b) -1/2,

(c) 0,

(d) 3.

Solution:

The smallest number is -1.

Answer: (a)

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.

Solution:

12a + 26b -4b – 16a.

= 12a – 16a + 26b – 4b.

= -4a + 22b.

Answer: (c)

4. Simplify: (4 – 5) – (13 – 18 + 2).

(a) -1,

(b) –2,

(c) 1,

(d) 2.

Solution:

(4 – 5) – (13 – 18 + 2).

= -1-(13+2-18).

= -1-(15-18).

= -1-(-3).

= -1+3.

= 2.

Answer: (d)

5. What is |-26|?

(a) -26,

(b) 26,

(c) 0,

(d) 1

Solution:

|-26|

= 26.

Answer: (b)


6. Multiply: (x – 4)(x + 5)

(a) x2 + 5x – 20,

(b) x2 – 4x – 20,

(c) x2 – x – 20,

(d) x2 + x – 20.

Solution:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x – 20.

Answer: (d)

7. Factor: 5x2 – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Solution:

5x2 – 15x – 20.

= 5(x2 – 3x – 4).

= 5(x2 – 4x + x – 4).

= 5{x(x – 4) +1(x – 4)}.

= 5(x-4)(x+1).

Answer: (a).

8. Factor: 3y(x – 3) -2(x – 3).

(a) (x – 3)(x – 3),

(b) (x – 3)2,

(c) (x – 3)(3y – 2),

(d) 3y(x – 3).

Solution:

3y(x – 3) -2(x – 3).

= (x – 3)(3y – 2).

Answer: (c).

9. Solve for x: 2x – y = (3/4)x + 6.

(a) (y + 6)/5,

(b) 4(y + 6)/5,

(c) (y + 6),

(d) 4(y – 6)/5.

Solution:

2x – y = (3/4)x + 6.

or, 2x – (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6).

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

Answer: (b).

10. Simplify:(4x2 – 2x) – (-5x2 – 8x).

Solution:

(4x2 – 2x) – (-5x2 – 8x)

= 4x2 – 2x + 5x2 + 8x.

= 4x2 + 5x2 – 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2)

11. Find the value of 3 + 2 • (8 – 3)

(a) 25,

(b) 13,

(c) 17,

(d) 24,

(e) 15.

Solution:

3 + 2 • (8 – 3)

= 3 + 2 (5)

= 3 + 2 × 5

= 3 + 10

= 13

Answer: (d)

12. Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?

Solution:

33/4 ÷ 4 pounds.

= (4 × 3 + 3)/4 ÷ 4 pounds.

= 15/4 ÷ 4 pounds.

= 15/4 × 1/4 pounds.

= 15/16 pounds.

Now we know that, 1 pound = 16 ounces.

Therefore, 15/16 pounds = 15/16 × 16 ounces.

= 15 ounces.

Answer: 15 ounces.

13. Factor: 16w3 – u4w3

Solution:

16w3 – u4w3.

= w3(16 – u4).

= w3(42 – ((u2)2).

= w3(4 + u2)(4 – u2).

= w3(4 + u2)(22 – u2).

= w3(4 + u2)(2 + u)(2 – u).

Answer: w3(4 + u2)(2 + u)(2 – u).


14. Factor: 3x4y3 – 48y3.

Solution:

3x4y3– 48y3.

= 3y3(x4 – 16).

= 3y3[(x2)2 – 42].

= 3y3(x2 + 4)(x2 – 4).

= 3y3(x2 + 4)(x2 – 22).

= 3y3(x2 + 4)(x + 2)(x -2).

Answer: 3y3(x2 + 4)(x + 2)(x -2)

15. What is the radius of a circle that has a circumference of 3.14 meters?

Solution:

Circumference of a circle = 2πr.

Given, the circumference = 3.14 meters.

Therefore,

2πr = Circumference of a circle

or, 2πr = 3.14.

or, 2 × 3.14r = 3.14,[Putting the value of pi (π) = 3.14].

or, 6.28r = 3.14.

or, r = 3.14/6.28.

or, r = 0.5.

Answer: 0.5 meter.

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